fire value for mortars

[wololoh]

Hi,

Thanks for your input. I'm still not seeing a rule which explains that the fire value linearly goes  to zero against hexes which are not fully stacked (edit: but I think Green is right in his last post, that the mortar fire is sort of treated the same way, although not exactly the same and not documented as far as I see. See also edit below)

"Artillery in Panzer Battles uses the ‘Alternate Indirect Fire Resolution rule’ as standard. In simple terms, you can only fire once, but that fire is doubled in strength and will impact all defending units in hex proportional to their strengths. Mortars and direct fire artillery (infantry guns) do not use this rule and can fire several times in a turn. "

I read this differently: namely that the impact of the fire is divided across the units proportional to their strenghts (i.e. when a large unit and small unit are stacked together, the losses are divided so that the large unit gets more losses than the smaller). Not that the fire value itself is impacted. (besides from the fact that mortars are excluded in the rule wording )

edit: did some testing with artillery. In the case of firing with artillery, the expected attack value seems doubled, and then each unit is attacked proportional to their strength (so indeed also for small units, the fire value goes to zero). For example firing at one infantry unit of 33 men has fire value 16, firing at a hex with three infantry units of 33 men has fire value 16 also, but applied to each unit separately.
(this example is for an attack which would have raw fire value 48, which is then multiplied by 2*33/200 per infantry unit of 33 men).

Is the fire occuring in your turn or is it opportunity fire (*0.5 effectiveness!, manual p. 47)

Note that for BzB Normandy, opportunity fire for the allies is actually 2* effectiveness ! (200% modifier in PDT, which is working as described by the way, I checked ). The rest of modifiers noted here are not applicable in the experiment.